C++ Mathematical Expression Toolkit (ExprTk) release
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exprtk_max_subarray_sum.cpp
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1/*
2 **************************************************************
3 * C++ Mathematical Expression Toolkit Library *
4 * *
5 * ExprTk Maximum Subarray Problem *
6 * Author: Arash Partow (1999-2024) *
7 * URL: https://www.partow.net/programming/exprtk/index.html *
8 * *
9 * Copyright notice: *
10 * Free use of the Mathematical Expression Toolkit Library is *
11 * permitted under the guidelines and in accordance with the *
12 * most current version of the MIT License. *
13 * https://www.opensource.org/licenses/MIT *
14 * SPDX-License-Identifier: MIT *
15 * *
16 **************************************************************
17*/
18
19
20#include <cstdio>
21#include <string>
22
23#include "exprtk.hpp"
24
25
26template <typename T>
28{
29 typedef exprtk::symbol_table<T> symbol_table_t;
30 typedef exprtk::expression<T> expression_t;
31 typedef exprtk::parser<T> parser_t;
32
33 const std::string max_subarray_sum_program =
34 " var zero := 0; "
35 " var curr_sum := 0; "
36 " var curr_start := 0; "
37 " "
38 " for (var i := 0; i < vec[]; i += 1) "
39 " { "
40 " curr_sum += vec[i]; "
41 " "
42 " if (curr_sum < zero) "
43 " { "
44 " curr_sum := 0; "
45 " curr_start := i + 1; "
46 " } "
47 " else if (curr_sum > max_sum) "
48 " { "
49 " max_sum := curr_sum; "
50 " max_start := curr_start; "
51 " max_end := i; "
52 " } "
53 " } ";
54
55 T max_sum = T(0);
56 T max_start = T(0);
57 T max_end = T(0);
58
59 T vec[] = { T(-1), T(-2), T(3), T(5), T(6), T(-2), T(-1), T(4), T(-4), T(2), T(-1) };
60
61 symbol_table_t symbol_table;
62
63 symbol_table.add_variable("max_sum" , max_sum );
64 symbol_table.add_variable("max_start", max_start);
65 symbol_table.add_variable("max_end" , max_end );
66 symbol_table.add_vector ("vec" , vec );
67
68 expression_t expression;
69 expression.register_symbol_table(symbol_table);
70
71 parser_t parser;
72 parser.compile(max_subarray_sum_program,expression);
73
74 expression.value();
75
76 if (max_start <= max_end)
77 {
78 printf("Max sum: %10.3f \n", max_sum);
79 printf("Start index: %4d\n", static_cast<int>(max_start));
80 printf("End index: %4d\n", static_cast<int>(max_end ));
81
82 for (int i = static_cast<int>(max_start); i <= static_cast<int>(max_end); ++i)
83 {
84 printf("%5.3f ",vec[i]);
85 }
86
87 printf("\n");
88 }
89 else
90 printf("No maximum sum found.\n");
91}
92
93int main()
94{
95 max_subarray_sum<double>();
96 return 0;
97}
void max_subarray_sum()